whats the pigeonhole principa?
Answer:
Area: pir^2
r=4
4pi^2
if pi=3.14
then the area is 50.24ft^2
Circumference: pi x d
d=8
8pi
if pi=3.14
then the circumference is 25.12ft.
Unit vector along the direction v = <3,1,-4> is :
![\hat{v} = \dfrac{3i + j -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}](https://tex.z-dn.net/?f=%5Chat%7Bv%7D%20%3D%20%5Cdfrac%7B3i%20%2B%20j%20%20-4k%7D%7B%5Csqrt%7B3%5E2%20%2B%201%5E2%20%2B%204%5E2%7D%7D%5C%5C%5C%5C%5Chat%7Bv%7D%20%3D%20%5Cdfrac%7B3i%20%2B%20j%20-4k%7D%7B5.1%7D)
So, unit vector opposing the
is :
![\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}](https://tex.z-dn.net/?f=%5Chat%7Bv%27%7D%20%3D%20-%5Chat%7Bv%7D%5C%5C%5C%5C%5Chat%7Bv%27%7D%20%3D%20-%28%20%5Cdfrac%7B3i%20%2B%20j%20-4k%7D%7B5.1%7D%29%5C%5C%5C%5C%5Chat%7Bv%27%7D%20%3D%20%5Cdfrac%7B-3i%20-%20j%20%2B4k%7D%7B5.1%7D)
so, vector of magnitude 3 units in opposite direction from v is :
![\vec{V} = 3\hat{v'}\\\\\vec{V} = \dfrac{3}{5.1}( -3i -j+4k)](https://tex.z-dn.net/?f=%5Cvec%7BV%7D%20%3D%203%5Chat%7Bv%27%7D%5C%5C%5C%5C%5Cvec%7BV%7D%20%3D%20%5Cdfrac%7B3%7D%7B5.1%7D%28%20-3i%20-j%2B4k%29)
Hence, this is the required solution.
The difference stance in between the chan
Answer:it’s i think maybe is 3/7 or 7/3
Step-by-step explanation: