Answer: how ever no negative number can really have a square root however it is possile to wokr with a more incluesive set of number so i belive no
Step-by-step explanation:
Answer:
There are no solutions for the pair of equations.
The lines are parallel to each other
Step-by-step explanation:
Line Q has a slope of 1/2 and crosses the y axis at 3.
This mean at x=0, y=3
Using the equation of a straight line expression to find the slope
y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;

For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c
The equation for S will be

Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.
Answer:
x=48
Step-by-step explanation:
Oops I forgot some degree symbols and forgot to take off some but the calculations are correct.
The answer is spring! :)
Hoped I helped!