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Mrrafil [7]
4 years ago
11

In triangle DEF, DK is the angle bisector of angle EDF. If EK=2, FK=5, and DF=10, what is the length of DE?

Mathematics
1 answer:
fiasKO [112]4 years ago
6 0

Answer:

4 units

Step-by-step explanation:

In triangle DEF, DK is the angle bisector of angle EDF.

<u>Angle bisector theorem</u> states that if a ray bisects an angle of a triangle, then it divides the opposite side into segments that are proportional to the other two sides.

Hence,

\dfrac{DE}{DF}=\dfrac{EK}{KF}

Thus,

\dfrac{DE}{10}=\dfrac{2}{5}\\ \\5DE=2\cdot 10\\ \\5DE=20\\ \\DE=4

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