3 × 
expressing as a whole number, using the digits available, we obtain
3
Now consider the position of the decimal point in the original 0.003
To get it back to where it should be we require to move the decimal point 3 places to the left , denoted by a negative exponent
0.003 = 3 ×
2^3x = 172
3x log 2 = log 172
3x = 7.4263
x = 2.475
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Wouldn't it be zero? because only 0 is less than 2 in this case
Answer: False
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Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
It represents 1/2, 50% or half of the equation.
it’s also the numerator, tells how many pieces you have from the whole.
