Answer: 0.07 (choice B)
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Explanation:
Let's define two events: B = hitting bullseye, and, T = hitting the third (outermost) ring
To figure out the probabilities of each event happening, we need to find the areas of each region. The bullseye is a circle with radius 6 inches (half of diameter 12), so the area is roughly...
A = pi*r^2 = pi*6^2 = 36pi
The radius of the outermost circle is 6+5+5 = 16 inches, leading to an area of
A = pi*r^2 = pi*16^2 = 256pi
So P(B) = (36pi)/(256pi) = 9/64 is the probability of hitting bullseye
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The area of the third ring is equal to the difference of the overall largest circle and the second largest circle.
The second largest circle has a radius of 6+5 = 11 inches with area pi*11^2 = 121pi square inches
So the third ring has an area of 256pi - 121pi = 135pi square inches
P(T) = probability of hitting the third ring
P(T) = (135pi)/(256pi)
P(T) = 135/256
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The last thing to do is to multiply the two probabilities P(B) and P(T). This works because the two events B and T are independent
P(B and T) = P(B)*P(T)
P(B and T) = (9/64)*(135/256)
P(B and T) = 0.07415771484376
P(B and T) = 0.07
Step-by-step explanation:
For 2 people it uses 1 1/3 cups
1 1/3 = 1.33
So for 4 people Tomas will use
1 1/3 + 1 1/3 = 2.66 or 2 2/3 cups
Answer:
Step-by-step explanation:
Add the two numbers and divide by 2, ,
Answer:
31 is the answer
Step-by-step explanation:
1+(6x5)
6x5 is 30 and then add 1
when 2 numbers are exactlky next to ach other you multiply them so therefore the answer is 30+1=31
Hope this helped :)
Mean: 52+62+55.55+54+62= 285.55
285.55/6= about 47.60
mode: is 54 or 62 (not sure about mode)
Median: 54, 54, 55.55, 62, 62, 64 is 55.55 + 62 (even number) = 117.55
117.55/ 2 = 58.775