So y=2x is the only answer that fit y=kx, while k=2
Answer:
75
Step-by-step explanation:
Step 1
Matt is ordering basketball jerseys For his country's league. Last year he ordered 512 jerseys. 64 those jerseys were orange.
The ratio of all Jerseys to Jerseys that are Orange =
512 : 64
8 : 1
Step 2
If he ordered 600 jerseys this year, how many of them will be Orange if the ratio of orange jerseys to all the jerseys remain the same?
Since we are maintaining the ratio in step 1
Let the number of orange jerseys = x
600 : x = 8 : 1
Hence
600/x = 8/1
Cross Multiply
8 × x = 600 × 1
8x = 600
x = 600/8
x = 75
Therefore, this year, the number of orange jerseys = 75
Answer:
(x,y)=(-13,-12)
Step-by-step explanation:
5x - 7y = 19
7x - 7y = -7 Multiply both sides of the equation by -1
Which then gives you :
5x-7y=19 Sum the equations vertically to eliminate
-7x+7y=7 at least on variable
-2x=26 Divide both sides of the equation by -2
X=-13 Substitute the given value of x into the equation 7x - 7y =-7
7 x(-13)-7y=-7 solve the equation for y
y=-12
Thus gives you (-13,-12)
Hope this was useful!!! Sorry if it's wrong.
If the long side on both is 9ft and 3ft then 3•3 is 9 so for the short side you do the same. If the short side is 1ft and the other is "j" then it's 1•3 is 3.
1•3=3
Sorry if it's confusing the way I explained it.
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
![d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5Bd_%7BFP%5C%20to%5C%20Clue1%7D%2Bd_%7BClue1%5C%20to%5C%20Clue2%7D%2Bd_%7BClue2%5C%20to%5C%20Clue3%7D%5D%2Adistance%5C%20per%5C%20unit%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%28Clue1_x-FP_x%29%5E2%2B%28Clue1_y-FP_y%29%5E2%7D%2B%5Csqrt%7B%28Clue2_x-Clue1_x%29%5E2%2B%28Clue2_y-Clue1_y%29%5E2%7D%2B%5Csqrt%7B%28Clue3_x-Clue2_x%29%5E2%2B%28Clue3_y-Clue2_y%29%5E2%7D%5D%2A%2Adistance%5C%20per%5C%20unit%5C%5C)
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.
