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KatRina [158]
3 years ago
10

Which point is inside the circle shown below?

Mathematics
2 answers:
Stolb23 [73]3 years ago
6 0
Letter be inside the circle
horrorfan [7]3 years ago
3 0
Since it's radius is 5,we can then find the range of the triangle that can be accepted.

As the centre is the mid-point,we can then find that:

the point at left-hand side is (-5,0),
while the point at the top would be (0,5),
and the point at the bottom would be (0,-5)

The range accepted would be: (-4~4,-4~4)
as the point has to be inside the circle,therefore excluding the range touching the circumference

Answer a. , c. and d. would then be impossible to be the answer as they're out of rhe range.

Thus the answer is b. (2, 3).

Sorry if it's a little complicated,do feel free to ask if you have asny question :)

Hope it helps!
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What is the unit rate of y=0.75x
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Joanne was hired by a florist to make large boes for holidays wreaths each roll of ribbon has 20 yards joanne used 3 1/2 rolls o
alukav5142 [94]

Answer: Each bow needs 4.67 yards of ribbon.

Step-by-step explanation:

We know that each roll has 20 yd.

She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:

(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.

With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:

70yd/15 = 4.67 yards

Each bow needs 4.67 yards of ribbon.

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Find the product. Simplify your answer.<br> -5 • 9t<br> 7s 7
Sauron [17]

Answer:

-13            

 ——— = -0.20635  

 63            

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           9

Equation at the end of step  1  :

 4    7

 — -  —

 7    9

Step  2  :

           4

Simplify   —

           7

Equation at the end of step  2  :

 4    7

 — -  —

 7    9

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       7  

     The right denominator is :       9  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

7 1 0 1

3 0 2 2

Product of all  

Prime Factors  7 9 63

     Least Common Multiple:

     63  

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 9

  Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4 • 9

  ——————————————————  =   —————

        L.C.M              63  

  R. Mult. • R. Num.      7 • 7

  ——————————————————  =   —————

        L.C.M              63  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

4 • 9 - (7 • 7)     -13

———————————————  =  ———

      63            63  

Final result :

 -13            

 ——— = -0.20635  

 63            

8 0
3 years ago
Read 2 more answers
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