To find the miles Michael rode, we can simply add up the miles he rode for both day:
Therefore the answer is 4 1/2 miles.
Hope it helps!
First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
The closest would be the Side-Side-Side (SSS) Similarity Theorem, which states that if the lengths of
the corresponding sides of two triangles are proportional, then
the triangles must be similar. But I don't know think that these are actually similar triangles...
It is letter C.) can u tell