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3 years ago

Without graphing, tell whether the line containing (4, 2) and (4, 9) is horizontal, vertical, or neither.

Mathematics

1 answer:

telo118 [61]3 years ago

4 0

Answer:

Vertical.

Step-by-step explanation:

It is vertical because 4 + 4 (adding both X-axis, totalling 8) is smaller than 9 + 2 (adding both Y-axis, totalling 11), so the Y-axis, which is vertical, is bigger.

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Courtney works at the local shoe store and receives $150 a week plus 3% of all sales over $1000. This week her sales were $3200.

schepotkina [342]

The equation you would use to find her earning for the week would be:

y=0.03(x-1000)+150

This would mean she made $66 from commissions and $216 total.

6 0

3 years ago

Helppp pt.5 plzzzzz

Fiesta28 [93]

Answer: 60 cm²

Step-by-step explanation:

This is pretty simple, we know AB is 12 cm and DE is 4 cm. We know ABC has a total of 180 square centimeters. So...

12 ÷ 3 = 4

180 ÷ 3 = 60

The answer is 60 cm²

I hope this helps!

6 0

3 years ago

Which of the following is a true statement

77julia77 [94]

Answer:

11/15 < 4/5

Step-by-step explanation:

1. 5/6 = 10/12, so the first answer is not correct

2. 1/4 = 4/16, so the second answer is not correct

3. 3/4 = 9/12 and 4/6 = 8/12, so the third answer is not correct

4. 4/5 = 12/15 > 11/15, so this answer is correct

7 0

2 years ago

Read 2 more answers

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

4 years ago

If 5x-3y=12 and 4x-5y=17 what is the value of y?

il63 [147K]

Answer:

Step-by-step explanation:

3 0

3 years ago