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Snezhnost [94]
3 years ago
9

HELLO can some one please HELP ME OUT !!!

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0
The answer is Quadrant 1
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What two whole numbers is the quotient between?
Katarina [22]

Answer:

Choice D

Step-by-step explanation:

38/4 =9.5

Therefore, this number is between 9 and 10

Note:

38/4 = 9 remainder 2

Hence, the quotient is 9 which is a whole number

3 0
3 years ago
A triangular courtyard has a perimeter of 120 meters. The lengths of two sides are 30 meters and 50 meters. How long is the thir
Masja [62]

Answer:

the third side is 40 m long

Step-by-step explanation:

The perimeter of the triangle is the sum of its three sides, and they give you what that value in meters is (120 m)

Your are given the length of two of them: 30 m and 50 m, and need to find the third one (let's call it "x" for this unknown side)

Now set the following equation:

Perimeter = side 1 + side 2 + side 3   --> replace these with the info you know

120 m = 30 m + 50 m + x   --> add 30 m and 50 m obtaining 80 m

120 m = 80 m + x  --> now solve for x (isolate the x on one side) by subtracting 80 m from both sides

120 m - 80 m = x  --> perform the subtraction 120 m - 80 m = 40 m

40 m = x

Which tells us that the third unknown side has a length of 40 m

7 0
4 years ago
Read 2 more answers
What is question a, b, c, d, e, and f? Thank you!
frosja888 [35]

Step-by-step explanation:

a. f(-4)= 2

b. f(0) = 0

c. f(3) = -1.8

d. f(-5) = 0

e. f(x) = -2 => x = 2

f. f(x) = 0 => x = 0 or -5

6 0
3 years ago
What is 35% of 500?<br> Help please
Hatshy [7]

Answer:

175

Step-by-step explanation:

500 times 35/100

simplify

8 0
3 years ago
Read 2 more answers
Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa
Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : \mu = 15.45

Standard deviation : \sigma = 13.70

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 5 degrees

z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76

For x= 10 degrees

z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40

The P-value : P(-0.76

=0.3445783-0.2236273=0.120951\approx0.1210

In percent , 0.1210\times100=12.10\%

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0
3 years ago
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