3 years ago

85 on a 7-hour clock

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer.

Step-by-step explanation:

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3 years ago

Solve the system of linear equations below 2x-y=0 3x-2y=-3

Lynna [10]

2x - y = 0
2x = y

3x - 2(2x) = -3
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3 years ago

Evaluate the expression 4x^4 y^3 when x=1/5 and y=6

wariber [46]

Answer:

5.5296

Step-by-step explanation:

to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6

4x^4 y^3

4 × x^4 × 4× y³

4 × (1/5)∧4 × 4 × 6³

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5.5296

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3 years ago

Please i need help realy fast or i will fail this semester

katrin2010 [14]

Y=mx+b
m=slope
b=yintercept

given
y=-2x+3 and
y=-4x-1

first equation is slope -2 and yintercept 3
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3rd option

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =

sveta [45]

Answer:

$\displaystyle n^3-\frac{1}{n^{2}}$

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

$(a^x)^y=(a^y)^x=a^{xy}$

$\displaystyle a^{-x}=\frac{1}{a^x}$

We are given the expression:

$2^m=n$

We need to express the following expression in terms of n.

$8^m-4^{-m}$

It's necessary to modify the expression to use the given equivalence.

Recall $8=2^3 \text{ and }4 = 2^2$ . Thus:

$(2^3)^m-(2^2)^{-m}$

Applying the property:

$(2^m)^3-(2^m)^{-2}$

Substituting the given expression:

$n^3-n^{-2}$

Or, equivalently:

$\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}$

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3 years ago