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LuckyWell [14K]
3 years ago
5

Place the indicated product in the proper location on the grid.

Mathematics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

See explanation

Step-by-step explanation:

1.

(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3=a^3+b^3

2.

(1-7x)(1+9x)=1+9x-7x-63x^2=-63x^2+2x+1

3.

(x+y+3)(x+y-4)=x^2+xy-4x+xy+y^2-4y+3x+3y-12=x^2+2xy+y^2-x-y-12

4.

(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3

5.

(m^3n+8)(m^3n-5)=(m^3n)^2-5m^3n+8m^3n-40=m^6n^2+3m^3n-40

6.

(4-(3c-1))(6-(3c-1))=(4-3c+1)(6-3c+1)=(5-3c)(7-3c)=35-15c-21c+9c^2=9c^2-36c+35

7.

(ab-9)(ab+8)=(ab)^2+8ab-9ab-72=a^2b^2-ab-72

8.

(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab

9.

(a+3)(a-2)=a^2-2a+3a-6=a^2+a-6

10.

(3m^3-y)(3m^3-y)=(3m^3)^2-3m^3y-3m^3y+y^2=9m^6-6m^3y+y^2

11.

(2x-3y)(4x-y)=8x^2-2xy-12xy+3y^2=8x^2-14xy+3y^2

12.

(x^2+2x-1)(x^2+2x+5)=x^4+2x^3+5x^2+2x^3+4x^2+10x-x^2-2x-5=x^4+4x^3+8x^2+8x-5

13.

(4x-3y+5)(x+2y-3)=4x^2+8xy-12x-3xy-6y^2+9y+5x+10y-15=4x^2+5xy-6y^2-7x+19y-15

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the average velocity of a car that travels 50 km in 2 hrs = 50/2 = 25 km/hrs

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WZ and XR are diameters what is thr measure of ZWX?
castortr0y [4]

Answer:

mZWX = 214°

Step-by-step explanation:

In a circle C, XR and WZ are two diameters.

∠ XCW = 34° and ∠ YCZ = 86°

We have to find the measure of arc ZWX

Since ∠XCW + ∠XCY + ∠YCZ = 180° [ angles on a straight line ]

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120° + ∠XCY = 180°

∠XCY = 180 - 120 = 60°

Now arc ZWX = 360° - (∠XCY + ∠ YCZ)

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8 0
3 years ago
Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, connuing un
jonny [76]

Answer:

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

Step-by-step explanation:

It is said that Actuary Rahul examines a low risk policy

Probability of a low risk policy having a claim = 10% = 0.1

Actuary Toby examines high risk policy

Probability of a high risk policy having a claim = 20% = 0.2

Let the number of policies examined by actuary Rahul before he finds a claim and stop be n

Probability that actuary Rahul examines exactly n policies =  0.9^{n-1} (0.1)

Probability that Toby examines more than n policies = 0.8^n

Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = 0.9^{n-1} (0.1) (0.8)^n

probability that both events happen simultaneously = \frac{0.1}{0.9} (0.72^{n})

The probability that Actuary Rahul examines fewer policies that Actuary Toby = \sum\limits^ \infty_1 {\frac{0.1}{0.9} 0.72^{n} } = \frac{1}{9}\sum\limits^ \infty_1 { 0.72^{n} } = \frac{1}{9} (\frac{0.72}{1-0.72} ) = \frac{1}{9} (\frac{0.72}{0.28} )

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

5 0
3 years ago
A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is
miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0
3 years ago
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