Answer:
x = 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality<u>
</u>
<u>Algebra I</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Identify</u>
<em>a</em> = 12
<em>b</em> = 5
<em>c</em> = x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [PT]: 12² + 5² = x²
- Evaluate exponents: 144 + 25 = x²
- Add: 169 = x²
- [Equality] Square root both sides: ±13 = x
- Rewrite: x = ±13
Since we are dealing with positive numbers, we can disregard the negative root.
∴ x = 13
Answer:
D: y = 3x² - 5x - 2
Step-by-step explanation:
The general form of a quadratic equation is: y = ax² + bx + c
c is the y-intercept
We are given the point (0, -2) which is the y-intercept, so we can rewrite our general form into
y = ax² + bx - 2
We can create a system of equations to solve for a and b. We are given two points.
Equation 1: Take the first point (-2, 20) and plug it into our general equation...
20 = a(-2)² + b(-2) - 2
20 = 4a - 2b - 2
22 = 4a - 2b (add 2 to both sides)
11 = 2a - b (divide both sides by 2 since every coefficient is even)
Equation 2: Take the point (1, -4) and plug it into the general equation
-4 = a(1)² + b(1) - 2
-4 = a + b - 2
-2 = a + b
Now we have our 2 equations:
11 = 2a - b
-2 = a + b
Since the coefficients of b are already have opposite signs, add the two equations together (elimination method)
Now we have
9 = 3a now solve for a...
3 = a (divide by 3 on both sides)
If a = 3, then
-2 = 3 + b
-5 = b
Our equation is
y = 3x² - 5x - 2
Answer
the answer would be C
Step-by-step explanation:
It seems like B is the answer.
Since the y values are being multiplied by 3 every time.
