I hope this helps you
121=11.11
a^2-11^2
(a-11). (a+11)
a.a+11a-11a-11.11
a^2+0-121
a^2-121
Answer:
The answer is 4
Step-by-step explanation:
3n+16=7n
collect like terms
-4n=-16
divide by -4
n=4
Let X represent a random variable representing the birth weights of babies, and let x be the required cut-off, then
P(X < x) = 0.02
P(z < (x - 3419)/494) = 0.02
1 - P(z < (3419 - x)/494) = 0.02
P(z < (3419 - x)/494) = 1 - 0.02 = 0.98
(3419 - x)/469 = 2.04
3419 - x = 956.76
x = 3419 - 956.76 = 2462.24
Therefore, the weight to be used as cut-off is 2462.24 g
It’s definitely d. -96,96
Hope this helps you!!!!!!!!!!
