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2 years ago

A triangle prism is shown below . What is the area of the diagonal surface BCFE shown?

Mathematics

1 answer:

Eddi Din [679]2 years ago

6 0

d = radical ( w^2 + l^2 + h^2)

h height

w wigth

l length

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Alicia buys a 5- pounds bag of rocks for a fish tank. She uses 1 1/8 pounds for a small fish bowl. How much is left?

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5 subtract 1 and one eighth is 3 and seven eighths
3 7/8

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3 years ago

Diane looks around at an assembly. She notices her younger sister to her right and her older brother 6 feet ahead of her. If Dia

UNO [17]

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2 years ago

Evalute The Expression 2b+5=2

Snezhnost [94]

Answer:

b = -3/2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Equation

2b + 5 = 2

Step 2: Solve for b

Subtract 5 on both sides: 2b = -3
Divide 2 on both sides: b = -3/2

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2 years ago

The points (–2, 4) and (–2, –2) are vertices of a heptagon. Explain how to find the length of the segment formed by these endpoi

Scrat [10]

Answer:

The segment is 6 units long.

Step-by-step explanation:

The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.

If two points at the ends of a straight line PQ are P( $x_{1},y_{1}$ ) and Q( $x_{2},y_{2}$ ), then the length of the segment PQ will be given by the formula

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$

Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be

$\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6$ units. (Answer)

5 0

3 years ago

Read 2 more answers

a(x+b)=4x+10 in the equation above a and b are constants. if the equation has infinitely many solutions for X, what is the value

xeze [42]

Answer:

$b= \frac{5}{2}$

Step-by-step explanation:

Given

$a(x+b)=4x+10\\ax+b= 4x+10\\$

Now we know that system has infinite solution for x

$\frac{a_1}{a_2}=\frac{b_1}{b_2}$

in above equation.

$a_1=a, a_2=4, b_1=ab,b_2=10\\$

∴ $\frac{a}{4}=\frac{ab}{10}\\\therefore b=\frac{10\times a}{4\times a}=\frac{5}{2}$

7 0

3 years ago