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pashok25 [27]
2 years ago
14

A triangle prism is shown below . What is the area of the diagonal surface BCFE shown?

Mathematics
1 answer:
Eddi Din [679]2 years ago
6 0

d = radical ( w^2 + l^2 + h^2)

h height

w wigth

l length

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Anyone who can help please do so but if you dont know the answer don't comment
KonstantinChe [14]
Tough one give me a couple min.
8 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
What’s is the value for X+8=12
Luba_88 [7]

Answer:

4

Step-by-step explanation:

X+8= 12

Carry over the 8 and make X the subject.

X= 12-8

X= 4

3 0
3 years ago
Read 2 more answers
A boat is carrying containers that weigh 4000 pounds each.
deff fn [24]

Answer:

4 = 16,000

8 = 32,000

10 = 40,000

Step-by-step explanation:

4 x 4 = 16 then add the zeros and then you have 16,000. Same thing with 8. 4 x 8 = 32 then add the zeros. Also goes for 10. 4 x 10 = 40 then add the zeros.

3 0
2 years ago
The graph shows how a motorboat travels around a lake. What does the graph most likely show?
kozerog [31]
D, it increases then goes at a constant speed
8 0
3 years ago
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