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777dan777 [17]
3 years ago
8

Can somebody help me with this quickly I forgot how to do this and yeah ill mark you!

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

4/11 i believe

Step-by-step explanation:

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Find the midpoint of the segment below and enter its coordinates as an
kodGreya [7K]

Answer:

(\frac{5}{2}, 3)

Step-by-step explanation:

I got 5/2 as my x variable and 3 for my y variable to being the midpoint. In which I added both my x variables provided ( 3 and 2 ) and then I divided them by two to get half of that (since you are looking for in between those two digits technically so you are wanting to find the midpoint or the middle of that line segment). I also did the same with the two y variables as well which were 7 and -1, then I divided both by two to get the variable 3.

4 0
3 years ago
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Evaluate the expression (3 • 2) to the second power
babymother [125]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
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Please answer quickly easy 15 points but please answer quick
vekshin1

Answer:

24.25 feet

Step-by-step explanation:

6 0
3 years ago
What is the projection of (4,4) onto (3,1)?
Ostrovityanka [42]
Let's define the vectors:
 U = (4.4)
 V = (3.1)
 The projection of U into V is proportional to V
 The way to calculate it is the following:
 Proy v U = [(U.V) / | V | ^ 2] V
 Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
 We have then:
 U.V Product:
 U.V = (4,4) * (3,1)
 U.V = 4 * 3 + 4 * 1
 U.V = 12 + 4
 U.V = 16
 Magnitude of vector V:
 lVl = root ((3) ^ 2 + (1) ^ 2)
 lVl = root (9 + 1)
 lVl = root (10)
 Substituting in the formula we have:
 Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
 Proy v U = [16/10] (3, 1)
 Proy v U = [1.6] (3, 1)
 Proy v U = [1.6] (3, 1)
 Proy v U = (4.8, 1.6)

 Answer:
 the projection of (4,4) onto (3,1) is:
 Proy v U = (4.8, 1.6)
6 0
3 years ago
PLSSS PEOPLE I NEED HELP
allochka39001 [22]

Answer:C

Step-by-step explanation:

The vertical line test

8 0
4 years ago
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