Answer:
The two roots of the quadratic equation are
Step-by-step explanation:
Original quadratic equation is 
Divide both sides by 9:
Add 
to both sides to get rid of the constant on the LHS
==> 
Add 
to both sides
This simplifies to
Noting that (a + b)² = a² + 2ab + b²
If we set a = x and b = 
we can see that
= 
So
Taking square roots on both sides
So the two roots or solutions of the equation are
and 
So the two roots are
and
Answer:
12a+2b
Step-by-step explanation:
1. Expand by distributing terms.
20a-8b-2(4a-5b)20a−8b−2(4a−5b)
2. Expand by distributing terms.
20a-8b-(8a-10b)20a−8b−(8a−10b)
3. Remove parentheses.
20a-8b-8a+10b20a−8b−8a+10b
4.Collect like terms.
(20a-8a)+(-8b+10b)(20a−8a)+(−8b+10b)
5. Simplify.
12a+2b12a+2b
6.Answer
12a+2b
Answer:
Step-by-step explanation:
(4 + 6) x 4 - 3
10 x 4 -3
40 -3
37
Using PEMDAS, 12-5 is 7. 7^2 is 49. 49+22=71. 71-3=68.
Answer:
X:-5, 2
Step-by-step explanation:
If you factor the expression, it becomes (x+5)(x-2). In order to make each expression in the paranthesis equal to 0, x must be -5 or 2.
