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olga nikolaevna [1]
3 years ago
12

This is prob really easy

Mathematics
2 answers:
Mrac [35]3 years ago
5 0

Answer:

3-(-2)=3+2 {The negative signs will become +)

and 3+2=5

so option 4 is correct

Zanzabum3 years ago
3 0

Answer:5

Step-by-step explanation:

whenever a negative is multiplied by a negative, it becomes a positive.

so: 3-(-2)—>3+2=5

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Find the 8th term of the geometric sequence 4 , − 20 , 100
fgiga [73]

Answer:

− 312500

Step-by-step explanation:

Whenever looking at sequences, you have to attempt to find a common factor between the members of that sequence, be it the difference between them, a common divisor, a common multiplier, etc. In this case, we can see that if we divide each member by the previous one, we get a the same number:

100/-20 = -5

-20/4 = -5

So our sequence, starting at 4 is represented by the following recursive equation:  

Hope this helps. :D

7 0
3 years ago
2.37E4 – 3.5E3<br> A) 2.02 x 104<br> A<br> B) 1.13 x 103<br> C) 5.87 x 104<br> D) 2.02 x 103
BaLLatris [955]

Answer:

Step-by-step explanation: roof I'm a

6 0
3 years ago
What is the factored form of X^9+27 A (x^3-3)(x^6+3x^3+9) B(x^3+3)(x^6-3x^3+9) C(x-3)^3(x^6+3x^3+9) D(x+3)^3(x^6-3x^3+9)​
irinina [24]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
2 years ago
What geometric term describes a corner f a living room
murzikaleks [220]
The answer is a vertex. Corners of any shape are vertexes
5 0
2 years ago
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