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IrinaVladis [17]
3 years ago
13

Help please help ..............................................

Mathematics
2 answers:
mina [271]3 years ago
5 0
Rs 9600 please give a thanks
postnew [5]3 years ago
4 0
Rs 9600 pls give Brainlyest
You might be interested in
If you rewrote these percents as fractions which one could be written as a whole number over 10? A. 1% B. 5% C.25% D. 40%
stiks02 [169]

Answer:

D. 40%

Step-by-step explanation:

Hi! All you basically need to do in this question is to really think. The tenths placement is what you are looking for.

Let us use money for example. a penny would represent 1%. It needs to be in tenths, 1/10, 2/10, 3/10, and so on to be a whole number. A penny is simplified to be only 1/100. This will not work.

B is 5%. This would represent a nickel. A nickel is simplified to be 1/20. This will not work. C is 25%. This would represent a quarter.

A quarter simplified is 2.5/10... not a whole number.

However 40% is 4/10, making it our answer.

Hope this helps!

8 0
3 years ago
Three girls (Zeva, Abby and Jenny) went to the hair salon. Each girl had their hair styled (curly, straight, and wavy) and color
Hoochie [10]

Answer:

Jenny= Blonde/Curly

Abby= Black/Straight

Zeva= Red/Wavy

Step-by-step explanation:

6 0
3 years ago
Simplify the expression.<br> -2 + 2/5b - 1/4b +6=
OleMash [197]

Answer:

3b/20+4

Step-by-step explanation:

-2 + 2/5b - 1/4b + 6

Combine 2/5b and 1/4b to get 3/20b

-2 + 3/20b + 6

Add −2 and 6 to get 4.

4+3/20b

8 0
3 years ago
I was never good with fractions, could someone help?
tangare [24]

Answer:

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Step-by-step explanation:

Considering the system of equations

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}

Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}\rightarrow \left[\begin{array}{ccc}1&1&1:2\\4&1&1:14\\1&-1&4:-14\end{array}\right]

R2 - 4 R1 → R2 (multiply 1 row by 4 and subtract it from 2 row); R3 - 1 R1 → R3 (multiply 1 row by 1 and subtract it from 3 row)

  \left[\begin{array}{ccc}1&1&1:2\\0&-3&-3:6\\0&-2&3:-16\end{array}\right]

R2 / -3 → R2 (divide the 2 row by -3)

\left[\begin{array}{ccc}1&1&1:2\\0&1&1:-2\\0&-2&3:-16\end{array}\right]

R1 - 1 R2 → R1 (multiply 2 row by 1 and subtract it from 1 row); R3 + 2 R2 → R3 (multiply 2 row by 2 and add it to 3 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&5:-20\end{array}\right]

R3 / 5 → R3 (divide the 3 row by 5)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&1:-4\end{array}\right]

R2 - 1 R3 → R2 (multiply 3 row by 1 and subtract it from 2 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&0:2\\0&0&1:-4\end{array}\right]

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Make a check:

4 + 2 + (-4) = 4 + 2 - 4 = 2

4·4 + 2 + (-4) = 16 + 2 - 4 = 14

4 - 2 + 4·(-4) = 4 - 2 - 16 = -14

Check completed successfully.

7 0
3 years ago
5a-2&lt;18a&lt;
Margarita [4]
The first one is (4) The second one is (-6) I'm not 101% sure but yeah.
8 0
3 years ago
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