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2 years ago

Find the missing side lengths. Leave your answer as radicals in simplest form.

Mathematics

2 answers:

Airida [17]2 years ago

6 0

Answer:

a = 9√2 and b = 9

Step-by-step explanation:

→ To find a, use the CAH triangle

9 ÷ cos (45) = 9√2

→ To find b, use the TOA

Tan (45) × 9 = 9

kirill [66]2 years ago

3 0

Answer:

Solution given:

b=9 base side of isosceles triangle

a= $\sqrt{9²+9²}=9\sqrt{2}$

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Please help I don't understand this very well<br>*picture*

Elenna [48]

Answer:

The inequality is 9 less than and equal to 5

The marked area on the line is numbers all below 5 which covers the less than and since it stop directly at 5 it's going to be equal to that as well

8 0

3 years ago

Read 2 more answers

A person can pay 18$ for a membership at a museum and then go for just 1$ per visit. What is the maximum number of visits a memb

Studentka2010 [4]

<h3>Answer: 32</h3>

==================================================

Work Shown:

Let

x = number of visits

y = total cost in dollars

The membership costs $18 no matter how many visits you do. If you make x visits, at $1 each, then it costs an additional 1*x = 1x = x dollars. This is added on top of the base membership fee. In total, we know that y = 18+x = x+18

We want the total y to be at most $50. Therefore $y \le 50$ . The highest y can get is 50.

Let's replace y with x+18 and isolate x

$y \le 50$

$x+18 \le 50$ y is replaced with x+18

$x+18-18 \le 50-18$ subtract 18 from both sides

$x \le 32$

This tells us that we can make at most 32 visits. In other words, the maximum number of visits is 32.

6 0

3 years ago

Type the correct answer in each box. Use numerals instead of words,

xeze [42]

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

8 0

3 years ago

A circle has a center at A (4,5), Determine the radius of the circle given two end points of the circle are B (9,5) and C (-1,5)

Anna71 [15]

ANSWER :

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.

4 0

3 years ago

Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

2 years ago