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Karolina [17]
3 years ago
9

HELP ASAP!!! thanks if you helped!

Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:

G. \frac{11}{20}

Step-by-step explanation:

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Pls answer with real answers only thank you (3)
DENIUS [597]

Answer:

15*20=300

15*16=240

20*57=1140

300+240+1140=<u><em>1680cm squared</em></u>

4 0
3 years ago
Read 2 more answers
May I please have help from anyone thank you so much !
FrozenT [24]

Answer: Choice D

======================================================

Explanation:

The formula for the surface area of a cylinder is

SA = 2\pi*r^2 + 2\pi*r*h

We then replace r with 10 and h with 25. Keep in mind that the diameter is 20 mm, so the radius is half that at 10 mm.

So that's how we get to

SA = 2\pi*10^2 + 2\pi*10*25

8 0
3 years ago
Read 2 more answers
Lori and Craig work in an apple orchard. One week, Craig picks 459 apples, and Lori picks four times as many apples as Craig. If
andreev551 [17]

Answer:

  765

Step-by-step explanation:

Craig picks 4 times 459 apples, or 1836 apples. The total number Lori and Craig picked is ...

  total apples = 459 +1836 = 2295

Each of the three equal groups will have 1/3 this number of apples, so will have ...

  1/3 × 2295 = 765 . . . apples

There are 765 apples in each group.

3 0
3 years ago
Which value of x makes the open sentence true? 10 +m2x&lt; 15x-20? 0, 1, 2,3
Zielflug [23.3K]

x=3 if the m was a typo, idk what that means

3 0
3 years ago
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N &lt;= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
3 years ago
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