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larisa86 [58]
3 years ago
10

M^3-8n^3 factor the sum and difference

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0
Factor: (M-2n)(M^2+2Mn+4n^2)
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Write the equation of the circle with center (0, 6) and radius 1.
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This is an equation in STANDARD form for a circle:

(x-h)^2 + (y-k)^2 = r^2

The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa. 

The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1. 

(x)^2 + (y-6)^2 = 1
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First what we must do is rewrite the table to find a solution:

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