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larisa86 [58]
3 years ago
10

M^3-8n^3 factor the sum and difference

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0
Factor: (M-2n)(M^2+2Mn+4n^2)
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Please tell me the answer quick
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To compare these numbers, you must first put them into one format.  Since you have mixed numbers, you may have to find and use the LCD.

-2.5, 1/5, 10, -12/4, 18/5, 10 could be simplified somewhat immediately:

-2.5, 1/5, 10, -3, (3 3/5)   This set of numbers is simple enough so that you could rearrange them in ascending order mentally:

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In this case the number of elements in this set is odd, so all you have to do is to select the MIDDLE element:  1/5.

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Answer:

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Answer:

She used GF = 2BG, but the correct statement is BG = 2GF.

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