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KIM [24]
3 years ago
7

What is the relationship between the two shapes

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0
Need the two shapes you forgot to add them
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Which equation represents a proportional relationship?<br> y=x/8 <br>y=-6 <br>y=2x+7 <br>y=5x+10​
adelina 88 [10]

Answer: the equation that best represents the data that is in the table is y = 5x. You can corroborate it by substituting the x values of the table and verifying that you get the "y" values

Step-by-step explanation: hopes this helps

3 0
3 years ago
What is angle X? <br> And pls explain
natita [175]

Answer:

angle x is an exterior angle of the triangle

3 0
3 years ago
The population density of the world is calculated by finding the ratio of the total number of people in the world to the area of
Romashka [77]

Answer:

51

Step-by-step explanation:

A = Surface area of the Earth = 1.5\times 10^8\ \text{km}^2

Total number of people on Earth = 7.594 billion as of 2018 = 7.594\times 10^9

We need to find the number of people living in each square km of land area.

So, we need to divide the number of people by the land area of the Earth.

1.5\times 10^8\ \text{km}^2=7.594\times 10^9\ \text{people}

\Rightarrow 1\ \text{km}^2=\dfrac{7.594\times 10^9}{1.5\times 10^8}

\Rightarrow 1\ \text{km}^2=50.63\approx 51\ \text{people}

So, 51 people will inhabit each square km of land area.

5 0
3 years ago
Mischa and Ben's combined SAT score was 2290. Ben and Ashley's
alexdok [17]

Answer:

Ashley=1450

Ben= 1080

Mischa= 1210

Step-by-step explanation:

M= Mischa

B= Ben

A= Ashley

M+B=2290

A+B=2530

M+A=2660

M-A= -240

so 2M = 2420, and M= 1210

Then

1210 + B = 2290

B= 1080

Then

1210 + A= 2660

A= 1450

5 0
3 years ago
A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
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