Question

rmula1" title="4 \times {2}^{ - \frac{t}{5} } = 288" alt="4 \times {2}^{ - \frac{t}{5} } = 288" align="absmiddle" class="latex-formula">
what is the solution to the equation?​

Answer 1

$~H~e~l~l~o~ !$

$\text{\underline{A N S W E R : }}$

$t = -1400$

$\boxed{\text{EXPLANATION :}}$

Multiply the numbers.

$4$  ·  $2 - 1$ · $\frac{t}{5} = 288$

$8 - 1$ · $\frac{t}{5} = 288$

Combine multiplied terms into a single fraction.

$8 - 1$ · $\frac{t}{5} = 288$

$8$ $+$ $\frac{-t}{5} = 288$

Subtract  8  from both sides of the equation.

$8 + \frac{-t}{5} = 288$

$\frac{-t}{5} = 280$

Multiply all terms by the same value to eliminate fraction denominators.

$\frac{-t}{5} = 2 8 0$

$5$ · $\frac{-t}{5} = 5$ ·  $280$

Cancel multiplied terms that are in the denominator.

$5$   ·  $\frac{-t}{5} = 5$ ·  $280$

$-t = 5$ · $280$

Multiply the numbers.

$-t = 5$ · $280$

$- t = 1400$.

Divide both sides of the equation by the same term.

$- t = 1400$

$\frac{-t}{-1} =\frac{1400}{-1}$

Simplify.

$t = - 1400$

Solution.

$- 1400$.

$\textit{ Hope It Helped! }$

$\text{\underline{A N S W E R : }}$

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