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3 years ago

Kylie draws a triangle on a coordinate grid. She then performs the following

Mathematics

1 answer:

zmey [24]3 years ago

7 0

B PLEASE GIVE BRAINLIEST

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ms green tell you that a right triangle has a hypotenuse of 13 and a leg of 5 . She asks you to find the other leg of the triang

Montano1993 [528]

Answer:

$\large \boxed{12}$

Step-by-step explanation:

We can apply Pythagoras' Theorem.

$\begin{array}{rcc}a^{2} & = & b^{2} + c^{2}\\13^{2}& = & 5^{2} + c^{2}\\169& = & 25 + c^{2}\\c^{2}& = & 144\\c & = & \sqrt{144}\\& = & \mathbf{12}\\\end{array}\\\text{The other leg of the triangle is $\large \boxed{\mathbf{12}}$}$

8 0

3 years ago

A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner

frozen [14]

Answer:

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner $I_{corner}$ is:

$I_{corner} = \int\limits \int\limits_R (x^2+y^2) \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx$

where :

(a and b are the length and the breath of the rectangle respectively )

$I_{corner} = \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx$

$I_{corner} = \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx$

$I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}$

$I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]$

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Thus; the moment of inertia of the lamina about one corner is $I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

7 0

3 years ago

What inequality does the graph represent?

slega [8]

The shaded region is above the line so it would be y> so then the equation is y=4x+2 since the graph has a y intercept of 2 and a slope of four

tl;dr the answer is B

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3 years ago

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What is 1/5 +2/4?the simplest form

timama [110]

Answer:

7 /10 0.7

Step-by-step explanation:

To add fractions, find the LCD and then combine.

5 0

3 years ago

Read 2 more answers