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Sav [38]
3 years ago
12

Help please if u can I really need if so ty

Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:hewwo I’m in school sorry for not talking to you

Step-by-step explanation:

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A builder has agreed not to erect all "look alike" homes in a new subdivision. Five exterior designs are offered to potential ho
shutvik [7]

Answer:

There will be 15 ways.

Step-by-step explanation:

5 exterior designs are offered to potential home buyers.

The builder has standardized 3 interior plans that can be incorporated in any of the 5 exteriors.

So, the number of different ways in which the exterior and interior plans be offered to potential home buyers is given by:

5\times3=15

Therefore, the answer is 15 ways.

4 0
3 years ago
Find x. 4 square root 3 2 square root 3 8 8 square root 3
UkoKoshka [18]

Answer:

8

Step-by-step explanation:

sin \:  \alpha  =  \frac{opp}{hyp}  \\ sin \: 30 =  \frac{4}{x}  \\  \frac{1}{2}  =  \frac{4}{x}  \\

x = 4 \times 2 \\ x = 8

6 0
3 years ago
What is the sum of ¾ + ⅔ in simplist form
natali 33 [55]

Answer:

The answer is 17/12

Step-by-step explanation:

3/4 + 2/3

= 9/12 + 8/12

= 9 + 8/12

= 17/12

7 0
3 years ago
Read 2 more answers
One way to recognize a line of symmetry is to look for a line that divides the original image into?
Hunter-Best [27]

Answer:

Half

Step-by-step explanation:

by dividing in half, it shows both sides are equal/symmetric

hope this helps:)

4 0
2 years ago
Read 2 more answers
PLEASE ANSWER ASAP!!!!
Arlecino [84]

We'll use the notation \textrm{Arcsin } x for the principal value and \arcsin x for all the values:


\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k


Part I


\sin(\theta/2) = \frac 1 2


\theta/2 = \arcsin \frac 1 2


Part II. In our range we can write


\sin(\theta/2) = \sin(\frac \pi 6)


\theta/2 = \frac \pi 6 \textrm{   or   } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}


Part III.


\theta = \frac \pi 3 \textrm{   or   } \theta = \frac{5\pi}{3}


Part IV.


\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k

\theta = \frac \pi 3 + 4 \pi k \textrm{   or   } \theta = \frac{5 \pi}{3} + 4\pi k  \quad \textrm{integer } k



5 0
3 years ago
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