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Yanka [14]
2 years ago
10

A library has five copies of a certain textbook on reserve of which two copies (1 and 2) are hardcover books and the other three

(3, 4, and 5) are softcover books. A student examines these books in random order, stopping only when a softcover book has been selected. One possible outcome is 5, and another is 213. (Enter your answers as a comma-separated list. Enter Ø for the empty set.)
Required:
a. List the outcomes in S
b. Let A denote the event that exactly one book must be examined. What outcomes are in A?
c. Let B be the event that book 5 is the one selected. What outcomes are in B?
d. Let C be the event that book 1 is not examined. What outcomes are in C?
Mathematics
1 answer:
Gre4nikov [31]2 years ago
5 0

Answer and Step-by-step explanation:

(a) Since the student have to stop when he gets to w softcover book, then the sample space should always stop at either 3 or 4 or 5. If the students examines the books randomly and stops at a softcover book, here are the possible ways he could carry this out,

S = {3, 4, 5, 13, 14, 15, 23, 24, 25, 123, 124, 125, 213, 214, 215}

2. Since only one book is to be examined then the student must check only one softcover book and end the examining. To do this, either he examines just 3 or 4 or 5. Therefore,

A = {3, 4, 5}

3. We need to pick the possibilities from the sample space that shows that the examining ended at book 5. Therefore,

B = {5, 15, 25, 125, 215}

4. We need to pick possibilities from the sample space that shows that book 1 was not examined. Therefore,

C = {3, 4, 5, 23, 24, 25}

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S - 10,000 = 3,753<br><br>A. s = 13,573<br><br>B. s = 13,753<br><br>C. s = 10,375
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Answer:

B. s = 13753

Step-by-step explanation:

s - 10000 = 3753

To find value of s, add both sides by 10000

s - 10000 = 3753

   +10000    +10000

-----------------------------------

s = 13753

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SOS if anyone could help that would be appreciated!!!❤️
Anastaziya [24]

Answer:

See below

Step-by-step explanation:

2e)15-4x=10x+45

Solve:

15-4x=10x+45\\-4x-10x=45-15\\-14x=30\\ \boxed {x=-\dfrac{15}{7}}3(x+1)=21

Check:

15-4 \left(-\dfrac{15}{7} \right)=10\left(-\dfrac{15}{7} \right)+45

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3a) 3(x+1)=21

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3c) -2(2x-3)=-2

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-2(2x-3)=-2\\-4x+6=-2\\-4x=-8\\x=2

3 0
3 years ago
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