$given \: that \: the \: cost \: of \: orchestra \: is \: three \: times \: of \: balcony \: ticket \\ let \: the \:cost \: of \: balcony \: \: ticket \: be \:x \\ so \: the \: cost \: of \: orchestra \: ticket \: sold \: be \: 3x \\ the \: total \: income = 3640 \\ \\ so \: the \: equation \: formed \: = > 148(3x)+ 76(x) = 3640 \\ = > 444x + 76x = 3640 \\ = > 520x = 3640 \\ = > x = \frac{3640}{520} \\ = > x = 7$

$so \: orchestra \: ticket \: = 444x = 444 \times = 3108 \\ and \: balcony \: ticket \: = 76x = 76 \times 7 = 532$

FOR PROOF = 3108+532 = 3640 total income

Hope it helps

5 0

3 years ago

Problem 1 a jar contains blue, red and green balls. the null-hypothesis h0 is that there is 25% percent of red balls. (1) a samp

Norma-Jean [14]

(1) the probability of that happening is .4444.. so on. the jar isnt 25% red balls because 25% of 36 is only 9 and he pulled out 16 red balls.

I dont know number two sorry.

5 0

3 years ago