Answer: 387 in base 10 to base 5 is 3022
Step-by-step explanation:
To convert 387 in base 10 to base 5, we would take the following steps
Firstly , we would divide the number to be converted by 5. The remainder forms the last digit of the number in base 5 while the quotient is divided again to get a new quotient and remainder. The new remainder forms the next digit to the left of the last digit. It continues till it gets to zero. Therefore,
387/5 = 77 remainder 2(last digit)
77/5 = 15 remainder 2(next digit to the left of the last).
15/5 = 3 remainder 0(next digit to the left)
3/5 = 0 remainder 3(next and final digit to the left)
Therefore, 387 in base 10 to base 5 is 3022
Answer:
You just have to divide 9 by 12 to get your answer of 75%
Answer: $3.20
Step-by-step explanation:
SI = p *r * t
= 5.93 * 0.06 * 9
= 3.20
Answer:
Verified
Step-by-step explanation:
Let the diagonal matrix D with size 2x2 be in the form of
![\left[\begin{array}{cc}a&0\\0&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%260%5C%5C0%26d%5Cend%7Barray%7D%5Cright%5D)
Then the determinant of matrix D would be
det(D) = a*d - 0*0 = ad
This is the product of the matrix's diagonal numbers
So the theorem is true for 2x2 matrices
14/20 21/30 28/40 are the equivalent fractions
