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Oxana [17]
3 years ago
12

Find the unknown angle. Show your work.

Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

x = 58

Step-by-step explanation:

By exterior angle theorem:

x \degree + 41 \degree = 99 \degree \\  \\ x \degree  = 99 \degree  -  41 \degree\\  \\  x \degree  = 58 \degree\\  \\ x = 58

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Select the correct answer.
ss7ja [257]

Answer:

B. (2,-5)

Step-by-step explanation:

The vertex of the function can be found in the most lower value that the function can have.

Since we have an ABS function involved we need to analyse it at first

We know that |x| = x if x> 0 and  |x| = -x if x< 0

if we now change x by x-2 (the content of our ABS function involved, we have the following

|x-2| = x-2 if x-2> 0

|x-2| = -x+2 if x-2< 0

Those inequaiities have a common solution

x-2=0, this means that x=2 is the lowest value the ABS(X-2) has and it is equals to zero.

So by evaluating x=2 in the given function we will obtain its vertex.

leading to f(2)=6 |2-2|-5= -5

Hence the point (2,-5) is the vertex of our function

5 0
3 years ago
WILL GIVE BRAINLIEST
mart [117]

Answer:

well the answer would be -22500 but I dont know where you would put it on a number line

6 0
1 year ago
Read 2 more answers
Please help me . it's simplifying expressions
Sergeu [11.5K]
Multiply in order
-8 * -8 = 64
64 * 5 = 320
320 * 5 = 1600
1600 * -8 = -12800
-12800 is your answer
8 0
4 years ago
What is the distance between the points (1, -4) and (1, 0)
tino4ka555 [31]

For this case we have that the distance between two points is given by:


d = \sqrt{(y2-y1)^2+(x2-x1)^2}

Given the points:


(x1, y1) = (1, -4)(x2, y2) = (1,0)

We substitute in the formula:


d = \sqrt{(0 - (- 4)) ^ 2 + (1-1) ^ 2}

d = \sqrt{(4 ^ 2 + 0 ^ 2)}

d=\sqrt{16}

d = 4

So, the distance is d = 4

Answer:


d = 4


5 0
3 years ago
What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid
devlian [24]
<h3>Answer:</h3><h3>Exact area = \frac{3}{2}\sqrt{3} square cm</h3><h3>Approximate area = 2.598 square cm</h3>

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

A = \frac{\sqrt{3}}{4}*s^2

A = \frac{\sqrt{3}}{4}*1^2

A = \frac{\sqrt{3}}{4}

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

6*A = 6*\frac{\sqrt{3}}{4}

6A = \frac{3\sqrt{3}}{2}

6A \approx 2.598

4 0
3 years ago
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