In the adjoining figure , O is the centre of the circle and PQ is the diameter .Show that angle PQR is a right angle .
1 answer:
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Answer:
sin (x) ≥ 0, between 0° and 180° or 0 and π,
sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6
Step-by-step explanation:
This is how I would do it. Subtract sin(x) from both sides
2 - sin(x) ≥ 0 , then factor out sin(x)
sin(x) [2 sin(x) - 1] ≥0, then set each factor ≥ 0
sin(x) ≥ 0 and 2 sin(x) - 1 ≥ 0
sin (x) ≥ 0, between 0° and 180° or 0 and π
2 sin(x) ≥ 1
sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6
