Nicholas is adding by place value from right to left. When he adds the hundredths, he gets 0.46. Describe what his next step sho
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<u>Answer:</u>
The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.
<u>Solution:</u>
Given, Scores on a test are normally distributed with a mean of 81.2
And a standard deviation of 3.6.
We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?
For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6
Now probability of getting more than 88.4 = 1 - area of z – score of 88.4
So, probability of getting more than 88.4 = 1 – area of z- score(2)
= 1 – 0.9772 [using z table values]
= 0.0228.
Now probability of getting more than 77.6 = 1 - area of z – score of 77.6
So, probability of getting more than 77.6 = 1 – area of z- score(-1)
= 1 – 0.1587 [Using z table values]
= 0.8413
Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185
Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.
Firstly, we'll fix the postions where the women will be. We have
forms to do that. So, we'll obtain a row like:
The n+1 spaces represented by the underline positions will receive the men of the row. Then,
Since there is no women sitting together, we must write that . It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:
The equation (i) can be rewritten as:
We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known:
[I can write the proof if you want]
Now, we just have to calculate the number of forms to permute the men that are dispposed in the row:
Multiplying all results:
Hello!
First you had to used apply rule -(-b)=b
Since the denominators are equal to it should be combine by the fractions.
Then add 4+2=6
Finally you had to cancel by the common factor of 3.
Hope this helps! And thank you for posting at here on Brainly. And have a great day! -Charlie :)