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garik1379 [7]
3 years ago
11

Nicholas is adding by place value from right to left. When he adds the hundredths, he gets 0.46. Describe what his next step sho

uld be. NO LINKS!!!!​
Mathematics
1 answer:
zzz [600]3 years ago
6 0

9514 1404 393

Answer:

  record 6 hundredths; add 4 to the numbers of tenths

Step-by-step explanation:

Nicholas needs to write down the 6 and "carry" the 4, adding it to the numbers of tenths.

Depending on the method you've been taught, the 4 may be written above the column with place value of tenths, or it may be written on a separate sum line.

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Graph ​ −8+x=4y−16 ​ Use the line tool and select two points on the line.
dimulka [17.4K]

Answer:

The two ordered pairs you can use is (4, 3) and (8, 4). You can plot these and draw a straight line through these.

Step-by-step explanation:

In order to find the graph of the follow, first solve for y.

-8 + x = 4y - 16

-4y - 8 + x = -16

-4y -8 = -x - 16

-4y = -x - 8

y = 1/4x + 2

Now that we have this, we can find two points by choosing any two x's and solving for the y. For this case, we'll use 4 and 8.

y = 1/4x + 2

y = 1/4(4) + 2

y = 1 + 2

y = 3

So the first ordered pair is (4,3)

y = 1/4x + 2

y = 1/4(8) + 2

y = 2 + 2

y = 4

So the second would be (8. 4)

6 0
3 years ago
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An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it f
alina1380 [7]
The end of its travel is when S(t)=0 or when it has hit the ground...

-16t^2+25=0  divide equation by -1

16t^2-25, this is a difference of squares which always factors:

(a^2+b^2)=(a+b)(a-b), in this case:

(4t+5)(4t-5)=0, since t>0

t=5/4=1.25, and since it started falling at t=0, its time moving in the air is:

1.25-0=1.25 seconds.
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3 years ago
Solve 7x +2x over 3 =5
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X= 15/9 — combine like terms to get 9x/3=15. Isolate the variable by multiplying both sides by 3. 9x=15 — divide both sides by 9 to isolate variable.
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What is 2 5/8 x 2/3. with the work shown
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Https://photomath.net/s/P56lb

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8 0
4 years ago
Part A. Find the orthogonal trajectories of the family of curves. (Use C for any needed constant.)x2 + 2y2 = 17k2Part B. Find th
kirill [66]

Answer:

Following are the solution to the question:

Step-by-step explanation:

The objective is to find the orthogonal trajectory of the family curves:

x^2+2y^2=17k^2

The family curves are: x^2 + 2y^2=17k^2  

Differentiate the equation with the respect of x.

\to x^2+2y^2=17k^2 \\\\\to 2x+4y \frac{dy}{dx} =0\\\\\to \frac{dy}{dx} =- \frac{2x}{4y}\\\\\to \frac{dy}{dx} =- \frac{x}{2y}

The negative reciprocal is:

\to \frac{dy}{dx} =-\frac{1}{-\frac{x}{2y}}\\\\\to \frac{dy}{dx} = \frac{2y}{x}

Integration of the above equation:

\to \frac{dy}{dx} = \frac{2y}{x} \\\\\to  \int \frac{dy}{2y} = \int \frac{dx}{x}\\\\\to  \frac{1}{2} \log y = \log x + \log C\\\\\to \log y = 2 \log x + 2\log C \\\\\to  \log y = \log x^2 +\log C^2 \\\\\to  y  = Ax^2   \ \ \ \ \ \ \ \ \ (A=C^2)

Hence, the orthogonal trajectory of the family of the curves x^2 + 2y^2 =17k^2 \ \ is \ \ y=Ax^2

6 0
3 years ago
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