We can build a system of two linear equations with two unknowns with the info provided in the problem, one with Kelsey info and one with Mitch info like so:
Lets call p the amount on peak minutes and n the amount of non-peak minutes:
45p + 50n = 27.75
70p + 30n = 36
lets reduce the equations dividing the first by 5:
9p + 10n = 5.55
<span>70p + 30n = 36
</span>now, to eliminate n, lets multiply the first equation by -3 and add the two equations:
-27p - 30n = -16.65
<span>70p + 30n = 36
</span>----------------------------
43p + 0 = 19.35
p = 19.35<span>/43
p = 0.45
therefore the peak rate is $0.45 per minute
lets substitute in one of the original equations this result:
</span><span>45p + 50n = 27.75
</span>45(0.45) + 50n = 27.75
20.25 <span>+ 50n = 27.75
50n = 27.75 - 20.25
50n = 7.5
n = 7.5/50
n = 0.15
therefore the non-peak rate per minute is $0.15</span>
To do this problem you need to find angle adc which is a part of angle BDA. angle BDA is 90 degrees so the 2 parts must add up to 90 degrees so you set up the problem like this
-2x + 144 - 3x +51 =90
then you combine like terms
-5x +195 = 90
then you subtract 195 from 90
-5x = -105
then you divide -5 by -5 and -105 by -5 and get
x=21
then you plug x in and get your angle measure
-3(21) +51
then you get the angle measure as 114 degrees.
I think it’s 60.5 dollars that they both earned altogether
Answer:
c 50
Step-by-step explanation:
Answer:
Use the formula,
Volume of cylinder =πr²h
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>3</em><em>.</em><em>1</em><em>4</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>1</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>5</em><em>5</em><em>2</em><em>.</em><em>6</em><em>4</em><em> </em><em>cm³</em>