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satela [25.4K]
1 year ago
5

What is the volume of the​ cylinder? Use 3.14 for . 4 cm 11 cm

Mathematics
1 answer:
Genrish500 [490]1 year ago
3 0

Answer:

Use the formula,

Volume of cylinder =πr²h

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>3</em><em>.</em><em>1</em><em>4</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>5</em><em>5</em><em>2</em><em>.</em><em>6</em><em>4</em><em> </em><em>cm³</em>

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Please Help! Thanks!
svetlana [45]

Answer:

C, 20 units

Step-by-step explanation:

We see that both angles QRS and QTR are 90 degrees. In addition, angles SQR and RQT are equivalent (because they're both angle Q).

By AA Similarity, we know that triangle QTR is similar to triangle QRS.

With this similarity in mind, we can look at the ratios of corresponding lengths to set up a proportion. QR from triangle QTR is the hypotenuse, and it corresponds to hypotenuse QS from triangle QRS. So, we can write the ratio x/(9 + 16) = x/25.

Now, we see that long leg QT of triangle QTR corresponds to long leg QR of triangle QRS. So, another ratio we can write is: 16/x.

Finally, we set these two ratios equal to each other:

\frac{x}{25} =\frac{16}{x}

Cross-multiplying, we get: x^{2} =16*25=400.

Thus, x = \sqrt{400} =20. The answer is C, 20 units.

Hope this helps!

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*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

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Similar to (21)

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For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

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Given is the inradius of an equilateral triangle.

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