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natita [175]
3 years ago
13

Y= 4.5x+ 7.5 y= -3.5x- 4.5

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0
What do you want the answer to? these are just equations and you never said what you want us to do with it
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An isosceles triangle has base angles that each measure 48°. Which equation can be used to find x, the measure of the third angl
Colt1911 [192]

Answer:

180-48/2

Step-by-step explanation:

180-48=

5 0
3 years ago
A population is estimated to have a standard deviation of 9. We want to estimate the population mean within 2, with a 99% level
cupoosta [38]

Answer:

The sample required is  n = 135

Step-by-step explanation:

From the question we are told that

     The  standard deviation is  \sigma = 9

      The margin of error is E =  2

     

Given that the confidence level is  99%  then the level of  significance is mathematically evaluated as

         \alpha =  100-99

        \alpha =  1 \%

        \alpha =  0.01

Next we will obtain the critical value  \frac{\alpha }{2} from the normal distribution table(reference  math dot armstrong dot edu) , the value is  

             Z_{\frac{\alpha }{2} } =  Z_{\frac{0.05 }{2} } =  2.58

The  sample size is mathematically represented as

          n = [ \frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ]^2

substituting values

           n = [ \frac{ 2.58 *  9 }{2} ]^2

            n = 135

3 0
3 years ago
HELP ME I NEED THE RIGHT ANSWER ONLY
Bas_tet [7]
The circumference and area of a circle with a diameter of 14 inches is A.
7 0
3 years ago
Read 2 more answers
Please !!!!!! Help me
PtichkaEL [24]

Answer:

a. 1 b. 3/5 or 60%

Step-by-step explanation:

number of favourable events/number of total events

3x/5x = 3/5

5 0
4 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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