Given:
x and y are both differentiable functions of t.
To find:
The value of 
.
Solution:
We have,
...(i)
At x=-1,
Divide both sides by 3.
Taking cube root on both sides.
So, y=2 at x=-1.
Differentiate (i) with respect to t.
Putting x=-1, y=2 and 
, we get
Divide both sides by -8.
Therefore, the value of is 36.
Answer:
- 16/5
Step-by-step explanation:
We have point with coordinates (-6, y) which lies ( or belong) on the graph of the straight line 5y=2x-4
When we replace x= -6 in given equation we get 5y = 2·(-6)-4 => 5y= -12-4 =>
5y= - 16 => y= - 16/5
Good luck!!!
I believe the expression that is equivalent to g+g+g+g+g+g is 6g. I'm not sure as you never sent a picture whatsoever.
Answer:
10+x+3x=-4(x-4)
10+2x=-4x+16
collect like-terms
2x+4x=16-10
6x=6
divide both by 6 to find the value of x
therefore, x is equal to 1
Answer:
BE equals CD times AB over AC
Step-by-step explanation:
took the test
