- m<1 = 145 | Supplementary
- m<3 = 35 | Vertical
- m<4 = 145 | Supplementary
- m<5 = 145 | (With Angle 4) If parallel then alternate interior angles congruent
- m<6 = 35 | (With Angle 5) Supplementary
- m<7 = 35 | (With Angle 6) Vertical
- m<8 = 145 | (With Angle 7) Supplementary
Hope it helps <3
(If it does, maybe brainliest :) Need one more for rank up)
Because when we draw a point ,we draw a very very small line....one can see how this might lead to a problem.consider a line that is 1 inch long,what we want to looked at 1/1000 through that line it would still be a line.but,if we drew it ,it would look like a point....
I dont know if this is what you are looking for but i think this is the answer of the question you are looking for which is the general equation of a horizontal hyperbola:
<span>(x-h)²/a² - (y-k)²/b² = 1 </span>
<span>with </span>
<span>center (h,k)
</span>What you need to do is replace the data and do the calculations
I think it’s 1.75 sorry if this is wrong
Answer:
The total number of apples is 17
Step-by-step explanation:
(a)
Number of green apples = 4
P ( that all three apples are green)
= (limit 4 and 3) / (limit 17 and 3)
= 4! / 3!(4−3)!
= 17! / 3!(17−3)!
= 1 / 170
= 0.005
(b)
Number of red apples = 8
P(that all three apple are green)
=(limit 8 and 3) / (limit 17 and 3)
= 8! / 3!(8−3)!
= 17! / 3!(17−3)!
= 7 / 85
= 0.082
Now,
P(that no three apple is red)= 1−0.082 = 0.918
c)
P(of selecting 4 apple that contain at least 2 red apples)
= (limit 8 and 2) /( limit 17 and 2) X (2/15) + (limit 8 and 3) /(limit 17 / 3) X (1/14)
= (7/34) × (2/15) + (7/85) × (1/14)
= 0.027 + 0.058
= 0.085
d)
P(that the second apple selected is yellow given that the first apple is red)
= (limit 5 and 1) / ( limit 16 and 1)
= 5! / 1!(5−1)!
= 16! / 1!(16−1)!
= 5 /16
= 0.3125
