Let y=f(x) be the particular solution to the differential equation dy/dx=2x−1/y^2 with the initial condition y(0)=3. Which of th
2 answers:
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Answer:
Please check the formatting when posting. I'm assuming these are the equations:
y=x^2 - 2
y=−x
Step-by-step explanation:
We can either graph the equations or solve them. I use graphing - see the attachment. The lines intersect at (-2, 2) and (1,-1)
<u>1. Graphing</u>
See attached graph
(-2, 2) and (1,-1) are the intersection points
<u>2. Solving</u>
y=x^2 - 2 Use y=−x in this equation:
-x = x^2 - 2
0 = x^2 + x - 2
0 = (x+2)(x-1)
x = -2 and +1
(-2, 2) and (1,-1) are the intersection points
Answer:
116.9 ft
Step-by-step explanation:
