Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Step-by-step explanation:
=9.8-6.4n
just add them together as easy as that
Answer:
-26
Step-by-step explanation:
first substitute -2 for x : 2(-2)+5(-2)-12
-4+-10-12
-14-12
-26
-26 is your answer
pls mark me brainliest if this helps !
