All categories

3 years ago

Which formula can be used to express the law of conservation of momentum, where p = momentum?

Mathematics

2 answers:

Anestetic [448]3 years ago

6 0

Answer:

The answer is A. pi=pf

Step-by-step explanation:

Just took the test

likoan [24]3 years ago

6 0

Answer: pi = pf

Step-by-step explanation:

Took the test on edgenuity and got it correct.

You might be interested in

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

4 years ago

QUICK HELP!!!!

sasho [114]

Answer:

$y = \frac{3}{4} x - \frac{3}{2}$

Step-by-step explanation:

$y = \frac{3}{4} x - 1→y - y1 = m( x - x1)$

$y - 6 = \frac{3}{4} (x - 6)→y - 6 = \frac{3}{4} x - 6$

$2(y - 6) = 2( \frac{3}{4} )(x - 6)$

$2y - 6= \frac{3}{2}( x - 6)$

$2y - 6 = \frac{3}{2} x - 9$

$- 6 \: from \: both \: sides$

$2y = \frac{3}{2} x - 3$

$divede \: by \: 2 \: on \: both \: sides$

$y = \frac{3}{4} x - \frac{3}{2}$

Hope this helps!

7 0

3 years ago

In the given figure find the value of x and y?<br>Show you works - Thank you!

Vaselesa [24]

<u>EXPLANATION</u><u>:</u>

In ∆ ABC , ∠ABC = 40°

∠CAB = x°
& ∠ACD = 50°

∠ACD is an exterior angle formed by extending BC to D

We know that

The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.

∠ACD = ∠CAB + ∠ABC

⇛50° = x° + 40°

⇛x° = 50°-40°

and

In ∆ ACD , AC = CD

⇛ ∠CDA = ∠CAD

Since the angles opposite to equal sides are equal.

Let ∠CDA = ∠CAD = A°

We know that

The sum of all angles in a triangle is 180°

In ∆ ACD,

∠CDA +∠CAD + ∠ACD = 180°

A°+A°+50° = 180°

⇛2A°+50° = 180°

⇛2A° = 180°-50°

⇛2A° = 130°

⇛A° = 130°/2

⇛A° = 65°

now,

∠CDA = ∠CAD = 65°

∠BAC + ∠CAD+y = 180°

Since angles in the same line

10°+65°+y = 180°

⇛75°+y =180°

⇛y = 180°-75°

<u>Answer</u><u>:</u> Hence, the value of “x” & “y” will be 10° and 105° respectively.

4 0

3 years ago

In choice box 1

lisov135 [29]

Answer:

Choice box 1: Always

Choice box 2: exactly 2 pairs

Choice box 3: adjacent

Step-by-step explanation:

If you look at a picture of a kite.

You always see the two top sides the same size and the two bottom sides the same size. Take a look at this picture.

8 0

2 years ago

Read 2 more answers

Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t) (in cm) as a function of time t (in s

xz_007 [3.2K]

Answer:

R (t) = 60 - 60 cos (6t)

Step-by-step explanation:

Given that:

R(t) = acos (bt) + d

at t= 0

R(0) = 0

0 = acos (0) + d

a + d = 0 ----- (1)

After $\dfrac{\pi}{12}$ seconds it reaches a height of 60 cm from the ground.

i.e

$R ( \dfrac{\pi}{12}) = 60$

$60 = acos (\dfrac{b \pi}{12}) +d --- (2)$

Recall from the question that:

At t = 0, R(0) = 0 which is the minimum

as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0

Similarly; 60 × 2 = maximum

R'(t) = -ab sin (bt) =0

bt = k π

here;

k is the integer

making t the subject of the formula, we have:

$t = \dfrac{k \pi}{b}$

replacing the derived equation of k into R(t) = acos (bt) + d

$R (\dfrac{k \pi}{b}) = d+a cos (k \pi)$ $= \left \{ {{a+d \ for \ k \ odd} \atop {-a+d \ for k \ even}} \right.$

Since we known a < 0 (negative)

then d-a will be maximum

d-a = 60 × 2

d-a = 120 ----- (3)

Relating to equation (1) and (3)

a = -60 and d = 60

∴ R(t) = 60 - 60 cos (bt)

Similarly;

For $R ( \dfrac{\pi}{12})$

$R ( \dfrac{\pi}{12}) = 60 -60 \ cos (\dfrac{\pi b}{12}) =60$

where ;

$cos (\dfrac{\pi b}{12}) =0$

Then b = 6

∴

R (t) = 60 - 60 cos (6t)

7 0

3 years ago