the quickest way to do this would be to multiply 1,375 by 3 and then add 2.
1,375 * 3 = 4,125 + 2 = 4,127
correct!
<span>v = 45 km/hr
u = 72 km/hr
Can't sketch the graph, but can describe it.
The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are
1. A segment from (0,0) to (80,60)
2. A segment from (80,60) to (110,60)
3. A segment from (110,60) to (160,120)
The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed.
120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr
After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that.
45 * 4/3 = 180/3 = 60 km.
So we have a good cross check that our initial speed was correct. v = 45 km/hr
Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time:
60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr
So the 2nd leg of the trip was at a speed of 72 km/hr</span>
Answer:
The expression 
does not represent a percent increase greater than 12%.
Step-by-step explanation:
We are asked to find whether the expression represent a percent increase greater than 12% if the original amount is x.
First of all, we will find 12% increase. The total amount after x% increase would be original amount plus 12% of original amount.
Since 1.12 is greater than 1.016, therefore, the expression does not represent a percent increase greater than 12%.
We can rewrite as:
Let us convert 
to percent by multiplying by 100.
Since 1.6% is less than 12%, therefore, the expression does not represent a percent increase greater than 12%.
The decimal equivalent of 3/10 is .3
The minimum happens at x = -b/2a
x = -30 / 2(3) = -30/6 = -5
Now replace x in the equation with -5 and solve:
3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48
The minimum is at (-5,-48)
