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Novosadov [1.4K]

3 years ago

10

I need working out and answers for the following:

1 answer:

LenaWriter [7]3 years ago

4 0

A. 4x - 3 = 2x + 7
4x - 2x = 7 + 3
2x = 10
x = 5

B. 2x + 6 = 7x - 14
2x - 7x = - 14 - 6
-5x = -20
x = 4

C. 2( x + 3) = x - 4
2x + 6 = x - 4
2x - x = -4 - 6
x = -10

D.4 ( 5x - 2) = 2( 9x + 3)
20x - 8 = 18x + 6
20x - 18x = 6 + 8
2x = 14
x = 7

E.4x - 1/2 = x - 7
4x - x = -7 + 1/2
3x = (-14 + 1)/2
3x = -13/2
x = -13/6

F. 3x + 2 = 2x + 13/3
3x - 2x = 13/3 - 2
x = (13 - 6)/3
x = 7/3

Hope This Helps You!

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DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Find out more on Congruent shape at: brainly.com/question/11329400

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Read 2 more answers

aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The parameters are given as follows:

$\mu = 959, \sigma = 263, n = 37, s = \frac{263}{\sqrt{37}} = 43.24$

Item a:

The probability is <u>one subtracted by the p-value of Z when X = 984</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{984 - 959}{263}$

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

Item b:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{984 - 959}{43.24}$

Z = 0.58

Z = 0.58 has a p-value of 0.7190.

1 - 0.719 = 0.281.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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2 years ago