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garik1379 [7]
3 years ago
14

A rectangle has a base of x squared y

Mathematics
1 answer:
jekas [21]3 years ago
8 0

Answer:

i don’t know

Step-by-step explanation:

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The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width , what are the dimensions?
lianna [129]
Let the length be \ell and the width be w. Now, write the length in terms of the width. "The length is 15 cm. less than twice the width" in the form of an equation is

\ell = 2w - 15 cm.

Let's plug that into the equation for the perimeter now. The perimeter of a rectangle is 2 \ell + 2w, so the equation for the perimeter of this rectangle is

2 \ell + 2w = 102 cm.

Plugging in the length in terms of width and solving for the width, we get

2(2w - 15 cm.) + 2w = 102 cm.
6w - 30 cm. = 102 cm.
6w = 132 cm.
\bf w = 22 cm.

To find the length, we just have to plug in the width into the equation we wrote for the length in terms of the width:

\ell = 2w + 15 cm.
\ell = 2(22 cm.) - 15 cm.
\bf \ell = 29 cm.
7 0
3 years ago
Can someone please help? just need help with the possibilities...
lana66690 [7]
Not sure about the last question
4 0
4 years ago
Read 2 more answers
I need help please<br><br> What is the area?<br><br> ____ Square millimeters
Lerok [7]
The area is 210 square millimeters
7 0
3 years ago
A concession stand at a sports stadium sells 600 bags of peanuts (each game) if the price of each bag is $4.00. For each $0.25 i
grin007 [14]

Answer:

Price = $4.50

Maximum revenue = $2,430

Step-by-step explanation:

The concession stand sells 600 bags of peanut at $4.00 (600, $4.00).

If there is a $1 increase in price, the number of bags old will decrease by 120, which mens that 480 bags of peanuts will be sold at $5.00 (480, $5.00).

Tracing a linear relationship between price and quantity sold with the two given points:

m = \frac{5-4}{480-600}\\ m=-\frac{1}{120}

P - P_0=m*(Q-Q_0)\\P-4.00=-\frac{1}{120} (Q-600)\\P= -\frac{1}{120}Q +9

The revenue function is given by the price multiplied by the quantity sold:

R=Q*P= (-\frac{1}{120}Q +9)*Q\\R=-\frac{1}{120}Q^2 +9Q

The value of 'Q' for which the derivate of the revenue function is zero, is the output level for which revenue is maximum:

R'=0=-\frac{2}{120}Q+9\\Q_{max} = 540\\P_{max} = -\frac{540}{120} +9\\P_{max} =\$4.50

The total revenue of 540 units at $4.50 per unit is:

R = \$4.50*540\\R=\$2,430

6 0
3 years ago
Plz Help, and solve. Show your work. I will give Brainliest. A - 7 = -13 solve and show your work 10X - 8 = 9X + 8 Can a right t
likoan [24]

Answer:

A - 7 = -13

Add 7

A = -6

10X - 8 = 9X + 8

Add 8

10X = 9X + 16

Subtract 9X

X = 16

In a right triangle, where a and b are the shorter sides, and c is the longer side a^2+b^2=c^2

Thus, plug in the values.

12^2+16^2=20^2

144+256=400

400=400.

Because the equation is true, 12, 16, and 20 can be a right triangle

<em>Hope it helps <3</em>

3 0
4 years ago
Read 2 more answers
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