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Wittaler [7]
2 years ago
7

a bird bath that is 3 ft talk casts a shadow that is 2 ft long.Find the height of a tent that casts a 6 ft shadow.

Mathematics
1 answer:
zheka24 [161]2 years ago
6 0

Answer:

is it 5ft

Step-by-step explanation:

if the bird bath had a foot taken off in the shadow then wouldn't a foot be taken off for the tent as well

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motikmotik

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external conflict

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Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
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The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
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V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
svet-max [94.6K]

Answer:

tan (C) = 2.05

Step-by-step explanation:

Given:

A right angled triangle CDE right angled at ∠D.

Side CD = 39

Side DE = 80

Side CE = 89

We know, from trigonometric ratios that, the tangent of any angle is equal to the ratio of the opposite side to the angle and the adjacent side of the angle.

Therefore, tangent of angle C is given as:

\tan(\angle C)=\frac{DE}{CD}

Plug in the given values and solve for angle C.This gives,

\tan(\angle C)=\frac{80}{39}\\\\\tan(\angle C)=2.051\approx 2.05(Rounded\ to\ nearest\ hundredth)

Therefore, the measure of tangent of angle C is 2.05.

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