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Wittaler [7]
3 years ago
7

a bird bath that is 3 ft talk casts a shadow that is 2 ft long.Find the height of a tent that casts a 6 ft shadow.

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

is it 5ft

Step-by-step explanation:

if the bird bath had a foot taken off in the shadow then wouldn't a foot be taken off for the tent as well

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Find the leading coefficient and write the factored form of the function of least degree for the polynomial in the graph below.
OLga [1]
Yyyiyoyjtjdnxhwhshshdhesjdjejd
3 0
2 years ago
K/7+3-2k=-3 what would K =
Aleonysh [2.5K]
I'm pretty sure k doesn't have a value it is no solution
3 0
3 years ago
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0
3 years ago
The length of the side of a regular nonagon is 7.86cm. Evaluate the perimeter of the nonagon.
Andru [333]

Answer: 70.74

Step-by-step explanation:

A Nonagon has 9 equal sides, and each side of the given is 7.86

So 7.86 multiplied by 9 is 70.74

3 0
3 years ago
A cylinder has a base radius of 10in and a height of 20in. What is its volume in cubic in, to the nearest tenths place?
irina1246 [14]

Answer:

6283.2

Step-by-step explanation:

V=\pi r^{2} h

==\pi *10^{2} *20

=6283.18531

=6283.2(correct to the tenths place)

5 0
2 years ago
Read 2 more answers
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