Answer:
![\vec u+m\vec v=](https://tex.z-dn.net/?f=%5Cvec%20u%2Bm%5Cvec%20v%3D%3C8%2C14%3E)
Step-by-step explanation:
Being
=<3,4> and
=<1,2>, we must find
![\vec u+m\vec v](https://tex.z-dn.net/?f=%5Cvec%20u%2Bm%5Cvec%20v)
If m is the magintude of
:
![m=\sqrt{a^{2}+b^{2}}](https://tex.z-dn.net/?f=m%3D%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D)
Where a and b are the components of ![\vec u](https://tex.z-dn.net/?f=%5Cvec%20u)
![m=\sqrt{3^{2}+4^{2}}=5](https://tex.z-dn.net/?f=m%3D%5Csqrt%7B3%5E%7B2%7D%2B4%5E%7B2%7D%7D%3D5)
![\vec u+5\vec v=+5=+=](https://tex.z-dn.net/?f=%5Cvec%20u%2B5%5Cvec%20v%3D%3C3%2C4%3E%2B5%3C1%2C2%3E%3D%3C3%2C4%3E%2B%3C5%2C10%3E%3D%3C8%2C14%3E)
Answer:
![x^{158}](https://tex.z-dn.net/?f=x%5E%7B158%7D)
Step-by-step explanation:
We are given,
.
It is required to find the value of y.
Now, on simplifying above equation, we get,
![x^{60} \times x^{-18} \times y = x^{200}](https://tex.z-dn.net/?f=x%5E%7B60%7D%20%5Ctimes%20x%5E%7B-18%7D%20%5Ctimes%20y%20%3D%20x%5E%7B200%7D)
i.e. ![x^{42} \times y = x^{200}](https://tex.z-dn.net/?f=x%5E%7B42%7D%20%5Ctimes%20y%20%3D%20x%5E%7B200%7D)
i.e. ![y = x^{200} \times x^{-42}](https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B200%7D%20%5Ctimes%20x%5E%7B-42%7D%20)
i.e. ![y = x^{158}](https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B158%7D)
Hence, the missing term is
.
First write it in vertex form :-
y= a(x - 2)^2 + 3 where a is some constant.
We can find the value of a by substituting the point (0.0) into the equation:-
0 = a((-2)^2 + 3
4a = -3
a = -3/4
so our equation becomes y = (-3/4)(x - 2)^2 + 3
Plug in the numbers wherever these letter are. Ex: 10x+5y. You would do 10x12=120 and 5x20=100. Add these two numbers to get 220. Hope this helps:)