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alexgriva [62]
3 years ago
13

What is the value of f^-1(-3)?​

Mathematics
1 answer:
poizon [28]3 years ago
8 0

Flip the curve over <em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>then observe what is y when x = -3. You will find that f^{-1}(x)=1.5.

Hope this helps.

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please help :( please help :( please help :( please help :( please help :( please help :( please help :( please help :( please h
egoroff_w [7]

Answer:

V= π×r×r×h

DATA

π= 22÷7

r×r =4

h=6

answer= 75.43

7 0
2 years ago
Read 2 more answers
Find the missing lengths: LK=15 and KH=9, find KI and HI.
Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

base^2+perpendicular^2=hypotenuse^2

Use Pythagoras in triangle HKL

LH^2+KH^2=LK^2

(LH)^2+9^2=15^2

(LH)^2+81=225

(LH)^2=144

Taking square root on both sides.

LH=12

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

(KI)^2+15^2=(12+x)^2

(KI)^2+225=x^2+24x+144

(KI)^2=x^2+24x+144-225

(KI)^2=x^2+24x-81...(1)

Use Pythagoras theorem in ΔHKI,

(KI)^2=x^2+9^2

(KI)^2=x^2+81...(2)

From (1) and (2) we get

x^2+81=x^2+24x-81

24x=162

x=\dfrac{162}{24}=6.75

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

(KI)^2=(6.75)^2+81

(KI)^2=126.5625

Taking square root on both sides.

KI=\sqrt{126.5625}

KI=11.25

Hence, the measure of KI is 11.25 units.

3 0
3 years ago
PLEASE HELP
Inessa [10]

Answer:

the measure of the missing length is 3 mi

Step-by-step explanation:

hey hey hey hey

6 0
2 years ago
Read 2 more answers
Find the value of 13 + (-7)
Vikki [24]

Answer:

6

Step-by-step explanation:

Before solve this you've to know that,

( + ) × ( - ) = ( - )

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

Let us solve now.

13 + (-7)

13 - 7

= 6

Hope this helps you :-)

Let me know if you have any other questions  :-)

7 0
2 years ago
Read 2 more answers
RE
serg [7]

Answer:

<h3>               d = - 4</h3>

Step-by-step explanation:

<h3> a_1=7\\a_2=3\\\\d=a_2-a_1=3-7=-4</h3>
4 0
3 years ago
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