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Arada [10]
3 years ago
14

Determine which of the following situations models a unit rate of $0.75. Select all situations that apply.

Mathematics
1 answer:
timurjin [86]3 years ago
4 0

Hello! :) The answers that I got was <span>Bottled water is on sale this week for a rate of $1.50 for two bottles and An online clothing store charges $7.50 to ship ten clothing items. To find the unit rate you must divide the total price/ total items= unit rate. So I did $1.50/2= 0.75 and $7.50/10= 0.75 That is how I got the answers. To double check multiply the unit rate you got multiplied by the items. Like for The bottle water I did $0.75*2=$1.50. </span>

<span>Hope I helped! :D </span>

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The company recently reduced its production to 1 million bicycles, but maintained its profit of 30 million dollars. What greater
Angelina_Jolie [31]

Answer:

1.3 million bicycles!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the measure of the largest angle in the
schepotkina [342]

Answer:

83°

Step-by-step explanation:

Fund the diagram attached. The sum of the ange in the triangle given is 180°, hence;

2x+1+x+15+x = 180

Collect like terms

2x+x+x+1+15 = 180

4x+16 = 180

4x = 180-16

4x = 164

x= 164/4

x =41

Out of the angles the largest angle is 2X+1

Get the largest angle;

2x+1 = 2(41)+1

=82 +1

= 83°

Hence the measure of the largest angle is 83°

6 0
3 years ago
Which expression has the same value as the one below? 87 + (-12)
hjlf

Answer:

75

Step-by-step explanation:

Given data

First term= 87

Second term= -12

Hence,

87 + (-12)

open bracket

+*-= -

= 87 -12

=75

Therefore the equivalent is 75

3 0
3 years ago
1. Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
gtnhenbr [62]
1. First, we are going to draw our triangle (picture 1). Next, we are going to use the cosine rule to find the length of side b:
b^2=a^2+c^2-2accosA
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{14^2+20^2-2(14)(20)cos(74)}
b=21.02
Now that we have all the sides of the triangle, we use Heron's formula to find its area. But first we need to find the semi-perimeter of the triangle. To do it, we are going to use the formula: s= \frac{a+b+c}{2}
where 
s is the semi-perimeter.
a, b, and c are the sides of the triangle. 

s= \frac{14+21.02+20}{2}
s= \frac{54.02}{2}
s=27.51

Now, we can use Heron's formula: A= \sqrt{s(s-a)(s-b)(s-c)}
where
A is the area of the triangle.
s is the semi-perimeter of the triangle.
a, b, and c are the sides of the triangle.
A= \sqrt{27.51(27.51-14)(27.51-21.02)(27.51-20}
A=134.59cm^2

The area of the triangle ABC is 134.59 square centimeters. We can conclude that the correct answer of your given choices is: 134.58 cm2 (your teacher made a little rounding error)

2. Just like before, the first thing we are going to do is draw the triangle (picture 2). Next, we are going to use the cosine rule to find the length of side b:
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{11^2+18^2-2(11)(18)cos(71)}
b=17.78

Semi-perimeter:
s= \frac{a+b+c}{2}
s= \frac{11+17.78+18}{2}
s=23.39

Heron's formula:
A= \sqrt{s(s-a)(s-b)(s-c)}
A= \sqrt{23.39(23.39-11)(23.39-17.78)(23.39-18)}
A=93.61cm^2

The area of triangle ABC is 93.61 square centimeters. We can conclude that the correct answer is <span>93.61 cm2

3. We have the vectors </span><span>P = (-5, 5) and Q = (-13, 6), and we want to find the vector 2 times PQ; in other words, we want to find the result of the multiplication between the vector initiating at P and ending at Q and the scalar 2.
First we are going to find the components of the vector </span>P and ending at Q:
PQ=\ \textless \ -13-(-5), 6-5\ \textgreater \
PQ=\ \textless \ -13+5, 1\ \textgreater \
PQ=\ \textless \ -8,1\ \textgreater \

Next, we are going to multiply the vector by the scalar 2:
2PQ=2\ \textless \ -8,1\ \textgreater \
2PQ=\ \textless \ -16,2\ \textgreater \

Now, we can find the magnitude of the vector. Remember that the magnitude of a vector is given by the Pythagorean theorem: |a|= \sqrt{x^2+y^2}
where
|a| is the magnitude of the vector 
\ \textless \ x,y\ \textgreater \ are the components of the vector.

We know that the components of the vector are x=-16 and y=2, so lets replace those vales in our equation: 
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{256+4}
|2PQ|= \sqrt{260}

We can conclude that the correct answer is: <span><-16, 2>, square root of two hundred and sixty.</span><span>
</span>

4 0
4 years ago
Pls help with this pls ​
Marta_Voda [28]

Answer:

9:17

Step-by-step explanation:

18 + 16 = total # of students = 34

18:34

9:17

Hope this helps!

5 0
2 years ago
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