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snow_lady [41]
3 years ago
12

What is the rate of change of the line through (10,-2) and (11, 14)?

Mathematics
1 answer:
zhenek [66]3 years ago
7 0

Answer:

Step-by-step explanation:

dy/dx=(y2-y1)/(x2-x1)

dy/dx=(-2-14)/(10-11)

dy/dx=-16/-1

dy/dx=16

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PLEASE ANSWER At a basketball game, 75% of people attending were supporting the home team, while 25% were supporting the visitin
Rufina [12.5K]

75% = 0.75

750 people / 0.75 = 1,000 people

There were 1,000 total people attending the game

6 0
3 years ago
Read 2 more answers
Given: ∠ABC Ξ ∠C E D, AB || CE<br> C is the midpoint of AD
Tems11 [23]

ΔABC ≅ ΔEDC by the SAS postulate.

<h3>What is the SAS postulate's conclusion?</h3>

Postulate of Side-Angle-Side (SAS) ,The two triangles are said to be congruent if two sides and the included angle of one triangle match those of another triangle by two sides and the included angle.

According to the SAS Postulate, two triangles are congruent if their two sides and included angles are identical to those of another triangle's two sides and included angle

The midpoint of DB and AE Given is at C.

BC ≅ CD Two equal portions are produced by the midway C.

AC ≅ CE Two equal portions are produced by the midway C.

ACB and DCE Congruent vertical angles exist.

By the SAS postulat, ABC becomes EDC.

To learn more about  SAS postulate refer to:

brainly.com/question/1311007

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4 0
2 years ago
What is the range of the function y = x2 +1 when the domain is {0, 2, 4}?
skad [1K]
You find the range by plugging 0 ,2 and 4 into x^2 + 1.

for x = 0   y = 0 + 1 = 1
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  x = 4  y =  4^2 + 1 =  17

so the range is  {1, 5, 17}
3 0
3 years ago
Determine the values of the constants B and C so that the function given below is differentiable.
laila [671]
For the function to be differentiable, its derivative has to exist everywhere, which means the derivative itself must be continuous. Differentiating gives

f'(x)=\begin{cases}24x^2&\text{for }x1\end{cases}

The question mark is a placeholder, and if the derivative is to be continuous, then the question mark will have the same value as the limit as x\to1 from either side.

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1}24x^2=24
\displaystyle\lim_{x\to1^+}f'(x)=\lim_{x\to1}B=B

So the derivative will be continuous as long as B=24

For the function to be differentiable everywhere, we need to require that f(x) is itself continuous, which means the following limits should be the same:

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}8x^3=8
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}Bx+C=24+C

24+C=8\implies C=-16

So, the function should be

f(x)=\begin{cases}8x^3&\text{for }x\le1\\24x-16&\text{for }x>1\end{cases}

with derivative

f'(x)=\begin{cases}24x^2&\text{for }x
5 0
4 years ago
Which shows how -2.65 can be written as the ratio of two integers
Ksju [112]

-265 / 100 = -2.65

simplifying a little

-53/20 = -2.65

8 0
3 years ago
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