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Anastasy [175]
3 years ago
5

2x+y=10------1 using substitution method

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0
Why is there a bunch of dash marks and then the number one...?
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10 pounds . = how many ounces
nignag [31]

Answer:

160oz

1lb=16oz

16*10=160

7 0
3 years ago
Read 2 more answers
which description best describes the solution to the following system of equations y= -2x +3 y= -x + 1
marin [14]
For this case we have the following system of equations:
 y = -2x +3

y = -x + 1
 Equating the values of y we have:
 -2x +3 = -x + 1

 From here, we can clear the value of x.
 We have then:
 -2x + x = 1 - 3

-x = -2

x = 2
 Then, we look for the value of y.
 For this, we substitute x in any of the equations:
 y = -x + 1

y = -2 + 1

y = -1
 Answer:
 
The ordered pair solution of the system of equations, is given by:
 
(x, y) = (2, -1)
3 0
3 years ago
Read 2 more answers
Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,
scoundrel [369]

Answer: \frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes

You know that he had 30 minutes in time-out, he counted spots on the ceiling for \frac{70}{3} minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and \frac{70}{3} minutes:

30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

7 0
3 years ago
Read 2 more answers
I'm completely loss I need help on the entire process to solve this problem
denis23 [38]
I cannot see the picture 
5 0
3 years ago
A mouse climbs up a well of 86 meters. It advances 14 meters during the night, but during the day it retreats 2. The mouse will
Deffense [45]

Step-by-step explanation:

we assume day and night are equally long.

and the mouse will start at night of day 1.

then, on day 2, it will first retreat 2 meters (during daylight) and then advance 14 meters (at night).

so, on every full day, the mouse will effectively advance 12 meters (-2 + 14 = 12).

with a starting value of 14 (the first night).

so, we are getting an arithmetic sequence

an = an-1 + c

c = 12 in our case.

a1 = 14

a2 = a1 + 12 = 14+12 = 26

a3 = a2 + 12 = a1 + 12 + 12 = 14 + 2×12 = 38

an = a1 + (n-1)×12 = 14 + 12(n-1)

at what n will it reach 86 ?

86 = 14 + 12(n-1) = 14 + 12n - 12 = 2 + 12n

84 = 12n

n = 7

so, on the 7th day the mouse will reach the surface (if we truly count the first starting night day 1 - this is up to your teacher, but I would).

7 0
2 years ago
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