-x+3y=10 find x and y intercept

1 answer:

8 0

$-x+3y=10 \\ \\
\hbox{x-intercept: } y=0: \\
-x+3 \times 0=10 \\
-x=10 \\
\boxed{x=-10} \\ \\
\hbox{y-intercept: } x=0: \\
-0+3y=10 \\
3y=10 \\
y=\frac{10}{3} \\
\boxed{y=3 \frac{1}{3}}$

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The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio

bixtya [17]

The correct option is (b) h=0.5cos( $\pi$ /6t)+9.5.

The equations can be used to model the height as a function of time, t, in hours is h=0.5cos( $\pi$ /6t)+9.5.

<h3>Equation of cosine function:</h3>

The following is a presentation of the cosine function's generic form;

y = a + cos(bx - c) + d

amplitude = a

b = cycle speed

Calculation for the model height;

The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.

Obtain amplitude 'a' as

$\begin{aligned}a &=\frac{\text { Maximum value }-\text { Minimum value }}{2} \\a &=\frac{10-9}{2} \\a &=\frac{1}{2} \\a &=0.5\end{aligned}$

The time 'T' is calculated as-

$\begin{aligned}&\mathrm{T}=\frac{2 \pi}{\mathrm{b}} \\&12=\frac{2 \pi}{\mathrm{b}} \\&\mathrm{b}=\frac{2 \pi}{12} \\&\mathrm{~b}=\frac{\pi}{6}\end{aligned}$

Now, calculate 'd'

$\begin{aligned}&\mathrm{d}=\frac{\text { Maximum value }+\text { Minimum value }}{2} \\&\mathrm{~d}=\frac{10+9}{2} \\&\mathrm{~d}=\frac{19}{2} \\&\mathrm{~d}=9.5\end{aligned}$

Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:

h=0.5cos( $\pi$ /6t)+9.5

To know more about the general equation of a cosine function, here

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The complete question is-

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.

A. h=0.5cos( $\pi$ /12t)+9.5

B. h=0.5cos( $\pi$ /6t)+9.5

C. h=cos( $\pi$ /12t)+9

D. h=cos( $\pi$ /6t)+9

7 0

2 years ago

Pls help me quickly

antoniya [11.8K]

What do I solve for?

4 0

3 years ago

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